Edexcel · GCSE Maths · 1MA1 · Foundation and Higher

M26 · Similarity and proportional measures

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Revision notes, worked examples and methods for similarity and proportional measures.

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Similar figures and scale factors

  • Similar figures have equal corresponding angles and proportional corresponding lengths. Congruent figures are the same size and shape, so their length scale factor is 1.
  • Identify corresponding sides using matching angles and position, rather than choosing sides simply because they look similar on the diagram.
  • Length scale factor from a smaller figure to a larger figure is . All corresponding lengths use the same factor.
    Two similar right-angled trianglesThe triangles have corresponding base lengths four and ten centimetres. Both their base and height scale by two point five.4 cm10 cmsmalllargeCorresponding length factor = 10 ÷ 4 = 2.5
    Two similar right-angled triangles
  • Worked example: A side of 4 cm corresponds to 10 cm, so scale factor is 2.5. A corresponding 6 cm side becomes 15 cm; reversing the enlargement uses factor 0.4.
  • For similar triangles, equal angles establish the same shape (AA similarity). This is not a congruence test: equal angles alone do not force equal side lengths.
  • Trigonometric ratios stay constant in similar right-angled triangles because corresponding sides scale together. This is why sin θ, cos θ and tan θ depend on the angle.
  • Perimeters scale by the length factor. If each length triples, a perimeter of 18 cm becomes 54 cm.

Higher — area and volume scaling

  • When the length factor is k, the area factor is k2 and the volume factor for similar solids is k3. Different dimensions require different powers.
    Scale length, area and volume. Unit-square and unit-cube scaling for length k, area k squared and volume k cubed
  • Worked example: Similar shapes with length ratio 2 : 5 have area ratio 4 : 25. An area of 12 cm2 on the smaller shape corresponds to 12 × = 75 cm2.
  • Worked example: Similar solids have length factor 3. Their volumes have factor 27, so a volume of 20 cm3 becomes 540 cm3.
  • To recover the length factor from an area factor, take a square root. An area factor 49 gives a length factor 7. From a volume factor 64, take a cube root to get 4.
  • If similar containers have volume ratio 8 : 27, their height ratio is 2 : 3 and their surface-area ratio is 4 : 9.
  • Mass scales like volume only if density is unchanged. Paint needed for a surface usually scales like area, whereas material filling a solid scales like volume.
  • Similarity must be established before applying square or cube scale rules. Changing just one dimension of a cuboid does not create a similar solid.

Test yourself

50 questions · Sets of 10 from the selected tier. For fractions, use / when typing; for powers, use superscripts or ^. Follow each question's answer format. These quick checks support revision; practise full written solutions and proofs too.

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Mind map

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M26 M26 mind map: Similar / congruent, Lengths, Area / volume, Applications. A text version follows.
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Similar / congruent

  • Correspondence: Similar: same angles, proportional sides; congruent: k=1
  • Triangles: AA proves similarity; not congruence; trig ratios unchanged

Lengths

  • Factor: Large/small matching lengths; reverse uses reciprocal
  • Perimeter: Every length ×k → perimeter ×k

Area / volume

  • Powers: Higher: Length k → area k² → volume k³
  • Reverse: Higher: Square root area factor; cube root volume factor

Applications

  • Material: Higher: Same density: mass follows volume; paint follows area
  • Condition: Higher: Establish similarity; changing one dimension is insufficient

Connections

  • Similar / congruent → Lengths: Matching sides determine one length factor
  • Area / volume → Applications: Dimensions determine square or cube scaling