Edexcel · GCSE Maths · 1MA1 · Foundation and Higher

M12 · Coordinates and straight-line graphs

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Revision notes, worked examples and methods for coordinates and straight-line graphs.

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Coordinates and gradients

  • Coordinates (x, y) give horizontal position first, then vertical position. In quadrant II, x is negative and y is positive; the origin is (0, 0).
  • The midpoint of (x₁, y₁) and (x₂, y₂) is (, ). The midpoint of (−2, 3) and (6, 7) is (2, 5).
  • A straight line has constant gradient m = . Use two well-separated points on the line; a positive gradient rises to the right.
    Graph of y equals two x plus oneThe line passes through zero one and two five. A gradient triangle rises four for a run of two.-101234-113579xyrun 2rise 4
    Graph of y equals two x plus one
  • Worked example: Through (1, 3) and (4, 9), m = = 2. Subtract the coordinates in the same order in numerator and denominator.
  • In y = mx + c, m is the gradient and c is the y-intercept. y = 2x + 1 passes through (0, 1), and goes up 2 for every 1 across.
  • To plot a line, calculate a table of values and draw a straight line through the points. Check the intercept and a third point to catch errors.
  • A horizontal line is y = k and has gradient 0. A vertical line is x = k; its gradient is undefined because the horizontal change is zero.

Finding line equations

  • Worked example: A line with gradient 3 through (2, 5) has 5 = 3 × 2 + c, so c = −1 and its equation is y = 3x − 1.
  • For a line through two points, find the gradient first, then substitute either point to find c. Through (1, 3) and (4, 9), y = 2x + 1.
  • Parallel non-vertical lines have equal gradients. y = 2x + 1 and y = 2x − 5 are parallel; different intercepts make them distinct lines.
  • Rearrange another line form to identify gradient: 2y = 6x − 4 becomes y = 3x − 2, so the gradient is 3, not 6.

Higher — perpendicular lines

  • For perpendicular non-horizontal, non-vertical lines, gradients satisfy m₁m₂ = −1. Take the negative reciprocal: the line perpendicular to gradient 2 has gradient −.
  • Worked example: Perpendicular to y = 2x + 1 through (4, 3): y = −x + c. Substitution gives 3 = −2 + c, so y = −x + 5.
  • A horizontal line is perpendicular to a vertical line. The negative-reciprocal rule should not be used by trying to divide by a zero gradient.

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M12 M12 mind map: Coordinates, Gradient, Line equation, Perpendicular. A text version follows.
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Coordinates

  • Order: (x,y): horizontal then vertical; signs identify quadrant
  • Midpoint: Average corresponding coordinates; (−2,3),(6,7) → (2,5)

Gradient

  • Rise / run: Change in y ÷ change in x; subtract in same order
  • Special lines: y = k horizontal: m=0; x = k vertical: undefined m

Line equation

  • Form: y = mx+c; m gradient, c y-intercept; table checks plot
  • Find c: Use gradient and a point; through (2,5), m=3 → y=3x−1
  • Rearrange / parallel: Get y alone to read m; parallel lines share gradient

Perpendicular

  • Reciprocal: Higher: Non-zero finite gradients: m₁m₂ = −1
  • Example: Higher: Perpendicular to m=2 through (4,3): y = −x/2+5
  • Exception: Higher: Horizontal and vertical lines are perpendicular

Connections

  • Coordinates → Gradient: Coordinate changes give the gradient
  • Gradient → Line equation: Gradient and a point determine a line